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=-2A^2+44A
We move all terms to the left:
-(-2A^2+44A)=0
We get rid of parentheses
2A^2-44A=0
a = 2; b = -44; c = 0;
Δ = b2-4ac
Δ = -442-4·2·0
Δ = 1936
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$A_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$A_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{1936}=44$$A_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-44)-44}{2*2}=\frac{0}{4} =0 $$A_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-44)+44}{2*2}=\frac{88}{4} =22 $
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